二叉树的遍历
  - 非递归 颜色判定法 中序遍历 迭代法,统一写法
 
/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    class ColorNode {
        TreeNode node;
        boolean flag; // true 为访问过; false 为未访问.
        ColorNode (TreeNode node, boolean flag) {
            this.node = node;
            this.flag = flag;
        }
    }
    public List<Integer> inorderTraversal(TreeNode root) {       
        if (root == null) return new ArrayList<Integer>();
        List<Integer> res = new ArrayList<>();
        ArrayDeque<ColorNode> stack = new ArrayDeque<>();
        stack.offerFirst(new ColorNode(root, false));
        while (stack.size() != 0) {
            ColorNode cn = stack.pollFirst();
            if (cn.flag == false) {
                //以下可以更改顺序
                if (cn.node.right != null) stack.offerFirst(new ColorNode(cn.node.right, false));
                stack.offerFirst(new ColorNode(cn.node, true));
                if (cn.node.left != null) stack.offerFirst(new ColorNode(cn.node.left, false));
            } else {
                res.add(cn.node.val);
            }            
        }
        return res;
    }
}
 1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
递归法 统一写法
/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    List<Integer> res=new ArrayList<>();
    public List<Integer> postorderTraversal(TreeNode root) {
        if(root==null) return res;
        
        //以下可以更改顺序
        if(root.left!=null) postorderTraversal(root.left);
        if(root.right!=null) postorderTraversal(root.right);
        res.add(root.val);
        return res;
    }
}
 1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
编辑  (opens new window)
  上次更新: 2024/02/22, 14:03:19